5(2-x)=2x^2+20

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Solution for 5(2-x)=2x^2+20 equation: 



5(2-x)=2x^2+20

We move all terms to the left:

5(2-x)-(2x^2+20)=0

We add all the numbers together, and all the variables

5(-1x+2)-(2x^2+20)=0

We multiply parentheses

-5x-(2x^2+20)+10=0

We get rid of parentheses

-2x^2-5x-20+10=0

We add all the numbers together, and all the variables

-2x^2-5x-10=0

a = -2; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·(-2)·(-10)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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